Whorl arithmetic -- Fibonacci sequence
In CotLS chapter 5, Maytera Marble/Rose thinks "... as predictably as the sixth term in a Fibonacci series of ten was an eleventh of the whole."
This is peculiar, because the Fibonacci series is:
1. 1
2. 1
3. 2
4. 3
5. 5
6. 8
7. 13
8. 21
9. 34
10. 55
The sum of the first ten terms is 143 = 11*13, so it's the seventh term that is the eleventh of the whole, not the sixth. The sum of the first nine terms is 88 = 11*8, which means the sixth term is the eleventh of the whole, as stated.
In base 9, our nine is represented as 10. To make the statement correct, we have to translate the "series of ten" in base-9 arithmetic and the "eleventh" in the decimal system.
Did the Maytera make a mistake, or did Wolfe, or should we revive the old base-9 controversy about Whorl arithmetic? There's another passage where the children seemingly make trvial arithmetic mistakes, as pointed out by Borski.
In Nightside the Long Sun, on p. 29, Wolfe has Maytera Marble presiding
1 quoted line
over a mathematics lesson, "watching the children take nineteen from twenty-nine and get nine, add seven and seventeen and get twenty-three." This, however, is only possible in a base 9 numbering system, and a strange one at that, since a conventional base 9 system would only include the digits 0 to 8 (there should thus no 9, 19, or 29).
Both statements could be correct if done in base 9, provided we solved the "9" representation problem and allow mixed translations:
(28+1)(base 9) - (18+1)(base 9) = 9 (decimal)
7(base 9) + 17(base 9) = 23 (decimal)
There might be some more clues involving costs with cards and bits, if we look for them.